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Joined 11 months ago
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Cake day: December 20th, 2023

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  • ulterno@lemmy.kde.socialtolinuxmemes@lemmy.worldSnap out of it
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    2 months ago

    If it’s C or C++, I get the source from the project’s GitHub / GitLab / Source Hosting thing and compile it for myself.
    For programming languages that I don’t read, I usually use the AUR.

    Also,

    • GoG for games
    • Xilinx website, for that one time, I got the ISE
    • AppImage sometimes






  • And more de-obf:

    #include <stdio.h>
    
    const char addarr1[]
    	= { 0x40, 0x40, 0x0,  0x40, 0x40, 0x40, 0x40, 0x0,  0x40, 0x40, 0x40, 0x40,
    		0x0,  0x40, 0x40, 0x40, 0x40, 0x40, 0x40, 0x0,  0x40, 0x40, 0x40, 0x0,
    		0x40, 0x0,  0x40, 0x40, 0x40, 0x40, 0x40, 0x0,  0x40, 0x40, 0x0,  0x40,
    		0x40, 0x40, 0x0,  0x40, 0x40, 0x40, 0x40, 0x0,  0x40, 0x40, 0x0,  0x40,
    		0x40, 0x40, 0x40, 0x40, 0x40, 0x0,  0x40, 0x40, 0x40, 0x40, 0x40, 0x40,
    		0x40, 0x40, 0x40, 0x40, 0x0,  0x40, 0x0,  0x0,  0x40, 0x40, 0x0,  0x40,
    		0x40, 0x0,  0x40, 0x40, 0x40, 0x40, 0x40, 0x40, 0x0,  0x40, 0x0,  0x40,
    		0x40, 0x40, 0x40, 0x0,  0x40, 0x40, 0x40, 0x40, 0x40, 0x40, 0x0,  0x0,
    		0x40, 0x0,  0x40, 0x40, 0x40, 0x0,  0x40, 0x0,  0x40, 0x40, 0x40, 0x40,
    		0x0,  0x0,  0x40, 0x40, 0x40, 0x0,  0x40, 0x40, 0x40, 0x40, 0x0,  0x40,
    		0x0,  0x40, 0x40, 0x0,  0x40, 0x40, 0x40, 0x40, 0x0,  0x40, 0x40, 0x0,
    		0x40, 0x40, 0x40, 0x40, 0x0,  0x40, 0x0,  0x40, 0x40, 0x40, 0x40, 0x0,
    		0x40, 0x40, 0x40, 0x0,  0x0,  0x0,  0x0,  0x0 };
    
    const char addarr2[]
    	= { 0x9,  0x26, 0x20, 0x39, 0x2f, 0x35, 0x32, 0x20, 0x2c, 0x2f, 0x36, 0x25,
    		0x20, 0x2c, 0x25, 0x34, 0x34, 0x25, 0x32, 0x20, 0x29, 0x33, 0x2e, 0x27,
    		0x34, 0x20, 0x27, 0x29, 0x36, 0x25, 0x2e, 0x20, 0x29, 0x2e, 0x20, 0x34,
    		0x28, 0x25, 0x20, 0x26, 0x2f, 0x32, 0x2d, 0x20, 0x2f, 0x26, 0x20, 0x28,
    		0x29, 0x27, 0x28, 0x2c, 0x39, 0x20, 0x2f, 0x22, 0x26, 0x35, 0x33, 0x23,
    		0x21, 0x34, 0x25, 0x24, 0x20, 0x3,  0x2c, 0x20, 0x29, 0x33, 0x20, 0x29,
    		0x34, 0x20, 0x32, 0x25, 0x21, 0x2c, 0x2c, 0x39, 0x20, 0x21, 0x20, 0x2c,
    		0x2f, 0x36, 0x25, 0x20, 0x2c, 0x25, 0x34, 0x34, 0x25, 0x32, 0x3f, 0xa,
    		0x9,  0x20, 0x24, 0x2f, 0x2e, 0x27, 0x34, 0x20, 0x2b, 0x2e, 0x2f, 0x37,
    		0x2c, 0x20, 0x22, 0x35, 0x34, 0x20, 0x37, 0x28, 0x21, 0x34, 0x20, 0x9,
    		0x20, 0x24, 0x2f, 0x20, 0x2b, 0x2e, 0x2f, 0x37, 0x20, 0x29, 0x33, 0x20,
    		0x34, 0x28, 0x21, 0x34, 0x20, 0x9,  0x20, 0x2c, 0x2f, 0x36, 0x25, 0x20,
    		0x39, 0x2f, 0x35, 0x21, 0x20, 0x3c, 0x33, 0xa };
    
    int main ()
    {
    	for (int i = 0; i < 152; i++)
    	{
    		char adder1 = addarr1[i];
    
    		char adder2 = addarr2[i];
    
    		char to_print = (char)adder1 + adder2;
    
    		printf ("%c", to_print);
    	}
    	return 63;
    }
    
    

    I guess I should have kept the recursion and straightened it out in the next step, but now that it’s done…

    The next step will just have an array of the characters that would be printed, so I’ll leave it here.


  • Here’s it with some amount of de-obfuscation:

    #include <stdio.h>
    short i = 0;
    const long b[]
    	= { 0xd60,  0x3200,  0x1ca8, 0x74e2, 0x9c,   0x66e8, 0x5100,  0x14500,
    		0x63b8, 0x49c6,  0xe0,   0x6200, 0x75e8, 0x57a6, 0xe8,    0x4300,
    		0x4500, 0x63b8,  0x49ea, 0xc6,   0x548e, 0x22,   0x75e8,  0x57a6,
    		0xc6,   0x2fae,  0x7486, 0x8a,   0xd72,  0x4f9c, 0x63c6,  0x4ea2,
    		0x809c, 0x66e8,  0x5100, 0x5c00, 0x71a2, 0x51b8, 0x4e9e,  0xc6,
    		0x6200, 0x70c4,  0x8022, 0x7d00, 0x439c, 0x63b8, 0x6ae0,  0x54c0,
    		0x47e8, 0xe2,    0x5192, 0x6fc4, 0x4900, 0x60e8, 0x100ca, 0x14fe8,
    		0x6000, 0x44e92, 0x6300, 0x57c4, 0xae,   0x4ecc, 0x62de,  0xc6,
    		0xafae, 0x70c4,  0x9e,   0x4ec6, 0x639c, 0x5100, 0x4ecc,  0x74a2,
    		0x9e,   0x54e8,  0x7100, 0x608a };
    const long n = 9147811012615426336;
    long
    main ()
    {
    	if (i < 152)
    	{
    		char shifter;
    		if (i % 2 == 0)
    		{
    			shifter = 8;
    		}
    		else
    		{
    			shifter = 1;
    		}
    		char adder1 = (b[i >> 1] >> shifter) & 64;
    
    		char adder2 = (n >> (b[i >> 1] >> shifter)) & 63;
    
    		char to_print = (char)adder1 + adder2;
    		i++;
    		main ();
    		printf ("%c", to_print);
    	}
    	return 63;
    }
    

    Needless to say, the return value doesn’t matter any more. So you can change it to 0 or 69 depending upon your preferences.